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Jefferson vs Leuzinger High

A head-to-head comparison of two schools in California, United States, 498 m apart, using official American 2025 data. The better value in each row is highlighted.

MeasureJefferson
Hawthorne, California
Leuzinger High
Lawndale, California
Success Index (US)
41
Lower 50%
22
Lower 50%
State rank#2478 of 5,693#1058 of 1,343
National rank#31458 of 50,301#14892 of 16,910
SectorPublicPublic
TypeElementaryHigh
Year rangeGrades Kโ€“5Grades 9โ€“12
Students5491,981
Enrollment5491,981
Free/reduced-price lunch89.3%83.2%
Students per teacher28.922.3
Reading proficiency57%46%
Math proficiency51%19%
cityHawthorneLawndale
stateCaliforniaCalifornia
Websiteโ€“โ€“

The verdict

  • โ€ขJefferson scores higher on the Success Index (US) (40.7 vs 22.3).
  • โ€ขJefferson does better on math proficiency (51% vs 19%).
  • โ€ขJefferson does better on reading proficiency (57% vs 46%).
  • โ€ขLeuzinger High does better on community advantage (fewer free/reduced-price lunch) (83.2% vs 89.3%).
  • โ€ขLeuzinger High does better on students per teacher (22.3 vs 28.9).
  • โ€ขLeuzinger High is the larger school with 1,981 students compared with 549.

The Success Index (US) summarises published results and context from official data. It does not measure teaching quality or fit. Methodology.

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Frequently asked questions

Is Jefferson better than Leuzinger High?

On the Success Index (US), Jefferson ranks higher (40.7 vs 22.3 out of 100). The index is built from published results and context data, not from teaching quality or fit, so visit both schools before deciding.

How far apart are Jefferson and Leuzinger High?

About 498 m in a straight line, between Hawthorne and Lawndale in California.

Which has the better Enrollment?

Jefferson: 549. Leuzinger High: 1,981. Students enrolled in the latest NCES directory year.

How do Jefferson and Leuzinger High rank in California?

Jefferson is 2478th of 5,693 and Leuzinger High is 1058th of 1,343 among elementary schools in California on the 2025 Success Index (US).