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Jefferson (Thomas) Elementary vs Scott M. Leaman

A head-to-head comparison of two elementary schools in California, United States, 638 km apart, using official American 2025 data. The better value in each row is highlighted.

MeasureJefferson (Thomas) Elementary
Anaheim, California
Scott M. Leaman
Lincoln, California
Success Index (US)
23
Lower 50%
57
Top 50%
State rank#4021 of 5,693#1517 of 5,693
National rank#42951 of 50,301#20023 of 50,301
SectorPublicPublic
TypeElementaryElementary
Year rangeGrades Kโ€“6Grades Kโ€“5
Students513513
Enrollment513513
Free/reduced-price lunch80.3%20.7%
Students per teacher23.324.4
Reading proficiency36%โ€“
Math proficiency32%โ€“
cityAnaheimLincoln
stateCaliforniaCalifornia
Websiteโ€“โ€“

The verdict

  • โ€ขScott M. Leaman scores higher on the Success Index (US) (57.4 vs 23.0).
  • โ€ขScott M. Leaman does better on community advantage (fewer free/reduced-price lunch) (20.7% vs 80.3%).
  • โ€ขJefferson (Thomas) Elementary does better on students per teacher (23.3 vs 24.4).

The Success Index (US) summarises published results and context from official data. It does not measure teaching quality or fit. Methodology.

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Frequently asked questions

Is Jefferson (Thomas) Elementary better than Scott M. Leaman?

On the Success Index (US), Scott M. Leaman ranks higher (57.4 vs 23.0 out of 100). The index is built from published results and context data, not from teaching quality or fit, so visit both schools before deciding.

How far apart are Jefferson (Thomas) Elementary and Scott M. Leaman?

About 638 km in a straight line, between Anaheim and Lincoln in California.

Which has the better Enrollment?

Jefferson (Thomas) Elementary: 513. Scott M. Leaman: 513. Students enrolled in the latest NCES directory year.

How do Jefferson (Thomas) Elementary and Scott M. Leaman rank in California?

Jefferson (Thomas) Elementary is 4021st of 5,693 and Scott M. Leaman is 1517th of 5,693 among elementary schools in California on the 2025 Success Index (US).