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Collinwood High School vs Fort Frye High School

A head-to-head comparison of two high schools in Ohio, United States, 223 km apart, using official American 2025 data. The better value in each row is highlighted.

MeasureCollinwood High School
Cleveland, Ohio
Fort Frye High School
Beverly, Ohio
Success Index (US)
12
Lower 50%
60
Top 50%
State rank#762 of 802#392 of 802
National rank#16430 of 16,910#5846 of 16,910
SectorPublicPublic
TypeHighHigh
Year rangeGrades 9โ€“12Grades 9โ€“12
Students228227
Enrollment228227
Free/reduced-price lunchโ€“63.4%
Students per teacher17.512.6
Reading proficiency24.5%62%
Math proficiency5%60%
cityClevelandBeverly
stateOhioOhio
Websiteโ€“โ€“

The verdict

  • โ€ขFort Frye High School scores higher on the Success Index (US) (59.8 vs 12.1).
  • โ€ขFort Frye High School does better on math proficiency (60% vs 5%).
  • โ€ขFort Frye High School does better on reading proficiency (62% vs 24.5%).
  • โ€ขFort Frye High School does better on students per teacher (12.6 vs 17.5).
  • โ€ขCollinwood High School is the larger school with 228 students compared with 227.

The Success Index (US) summarises published results and context from official data. It does not measure teaching quality or fit. Methodology.

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Frequently asked questions

Is Collinwood High School better than Fort Frye High School?

On the Success Index (US), Fort Frye High School ranks higher (59.8 vs 12.1 out of 100). The index is built from published results and context data, not from teaching quality or fit, so visit both schools before deciding.

How far apart are Collinwood High School and Fort Frye High School?

About 223 km in a straight line, between Cleveland and Beverly in Ohio.

Which has the better Enrollment?

Collinwood High School: 228. Fort Frye High School: 227. Students enrolled in the latest NCES directory year.

How do Collinwood High School and Fort Frye High School rank in Ohio?

Collinwood High School is 762nd of 802 and Fort Frye High School is 392nd of 802 among high schools in Ohio on the 2025 Success Index (US).