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Jane Long vs Stephen F Austin

A head-to-head comparison of two middle schools in Texas, United States, 3.0 km apart, using official American 2025 data. The better value in each row is highlighted.

MeasureJane Long
Bryan, Texas
Stephen F Austin
Bryan, Texas
Success Index (US)
27
Lower 50%
36
Lower 50%
State rank#1491 of 1,684#1244 of 1,684
National rank#12449 of 15,369#10697 of 15,369
SectorPublicPublic
TypeMiddleMiddle
Year rangeGrades 5โ€“6Grades 7โ€“8
Students8951,177
Enrollment8951,177
Free/reduced-price lunch86.9%73.8%
Students per teacher14.714.7
Reading proficiency27%40%
Math proficiency36%35%
cityBryanBryan
stateTexasTexas
Websiteโ€“โ€“

The verdict

  • โ€ขStephen F Austin scores higher on the Success Index (US) (35.8 vs 27.2).
  • โ€ขJane Long does better on math proficiency (36% vs 35%).
  • โ€ขStephen F Austin does better on reading proficiency (40% vs 27%).
  • โ€ขStephen F Austin does better on community advantage (fewer free/reduced-price lunch) (73.8% vs 86.9%).
  • โ€ขStephen F Austin is the larger school with 1,177 students compared with 895.

The Success Index (US) summarises published results and context from official data. It does not measure teaching quality or fit. Methodology.

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Frequently asked questions

Is Jane Long better than Stephen F Austin?

On the Success Index (US), Stephen F Austin ranks higher (35.8 vs 27.2 out of 100). The index is built from published results and context data, not from teaching quality or fit, so visit both schools before deciding.

How far apart are Jane Long and Stephen F Austin?

About 3.0 km in a straight line, between Bryan and Bryan in Texas.

Which has the better Enrollment?

Jane Long: 895. Stephen F Austin: 1,177. Students enrolled in the latest NCES directory year.

How do Jane Long and Stephen F Austin rank in Texas?

Jane Long is 1491st of 1,684 and Stephen F Austin is 1244th of 1,684 among middle schools in Texas on the 2025 Success Index (US).