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Bloomington School vs Desert Hills High

A head-to-head comparison of two schools in Utah, United States, 2.3 km apart, using official American 2025 data. The better value in each row is highlighted.

MeasureBloomington School
ST George, Utah
Desert Hills High
Saint George, Utah
Success Index (US)
64
Top 50%
63
Top 50%
State rank#138 of 580#23 of 148
National rank#15768 of 50,301#4953 of 16,910
SectorPublicPublic
TypeElementaryHigh
Year rangeGrades PKโ€“5Grades 10โ€“12
Students5531,241
Enrollment5531,241
Free/reduced-price lunch25.9%12.2%
Students per teacher19.827.0
Reading proficiency58%58%
Math proficiency57%56%
cityST GeorgeSaint George
stateUtahUtah
Websiteโ€“โ€“

The verdict

  • โ€ขBoth schools have almost identical Success Index (US) scores (63.5 vs 63.3).
  • โ€ขBloomington School does better on math proficiency (57% vs 56%).
  • โ€ขDesert Hills High does better on community advantage (fewer free/reduced-price lunch) (12.2% vs 25.9%).
  • โ€ขBloomington School does better on students per teacher (19.8 vs 27.0).
  • โ€ขDesert Hills High is the larger school with 1,241 students compared with 553.

The Success Index (US) summarises published results and context from official data. It does not measure teaching quality or fit. Methodology.

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Frequently asked questions

Is Bloomington School better than Desert Hills High?

The two schools are very close on the Success Index (US). Differences in sector, size, programmes and distance from home will matter more than the score.

How far apart are Bloomington School and Desert Hills High?

About 2.3 km in a straight line, between ST George and Saint George in Utah.

Which has the better Enrollment?

Bloomington School: 553. Desert Hills High: 1,241. Students enrolled in the latest NCES directory year.

How do Bloomington School and Desert Hills High rank in Utah?

Bloomington School is 138th of 580 and Desert Hills High is 23rd of 148 among elementary schools in Utah on the 2025 Success Index (US).